Remove element based on child element value with XSLT

Question

After reading this answer and also this one I'm still quit confused how to remove an element (parent) based on another element (child) value. This is the example xml:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Order>
    <Orderline>
        <Itemcode>ABC</Itemcode>
        <Qty>0</Qty>
    </Orderline>
    <Orderline>
        <Itemcode>XYZ</Itemcode>
        <Qty>3</Qty>
    </Orderline>
    <Orderline>
        <Itemcode>DFG</Itemcode>
        <Qty>0</Qty>
    </Orderline>
</Order>

This is the XLST I currently have:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="node()|@*">
  <xsl:copy>
   <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match=
 "*[Qty='0']/Itemcode | *[Qty='0']/Qty "/>
</xsl:stylesheet>

Which produces this result:

 <Order>
    <Orderline/>
    <Orderline>
        <Itemcode>XYZ</Itemcode>
        <Qty>3</Qty>
    </Orderline>
    <Orderline/>
</Order>

How can you remove the empty <Orderline/> element as well? The idea is to remove <Orderline> , <Itemcode> and <Qty> elements if value of Qty = 0

Answer 1

This:

<xsl:template match="*[Qty='0']/Itemcode | *[Qty='0']/Qty "/>

matches either Itemcode or Qty , so those are the nodes that end up removed. In order to remove the entire Orderline with all its descendants, you only have to do:

<xsl:template match="Orderline[Qty='0']"/>