<style>
.faq ul li {
display: block;
float: left;
padding: 5px;
}
.faq ul li div {
display: none;
}
.faq ul li div:target {
display: block;
}
</style>
<div class="faq">
<ul>
<li><a href="#question1">Question 1</a>
<div id="question1">Answer 1 </div>
</li>
<li><a href="#question2">Question 2</a>
<div id="question2">Answer 2 </div>
</li>
<li><a href="#question3">Question 3</a>
<div id="question3">Answer 3 </div>
</li>
<li><a href="#question4">Question 4</a>
<div id="question4">Answer 4 </div>
</li>
<li><a href="#question5">Question 5</a>
<div id="question5">Answer 5 </div>
</li>
<li><a href="#question6">Question 6</a>
<div id="question6">Answer 6 </div>
</li>
</ul>
</div>
I found this great link http://jsfiddle.net/ionko22/4sKD3/ regarding collapsible
div using CSS. Is there a way to have question 1 always open without clicking on it when you visit the page. And make it collapse when you click on any other questions. Also is there a way to close
the div/questions by clicking on itself? I would be very grateful if you can reply to this.
http://jsfiddle.net/4sKD3/821/
Add this to the CSS to make the first question appear by default:
.faq ul li:first-of-type div {
display: block;
}
And add this jQuery for toggling:
$(".faq ul li").click(function() {
if( $( this ).children( "div" ).css( "display" ) == "none" ) {
$( ".faq ul li div" ).hide();
$( this ).children( "div" ).show();
} else {
$( ".faq ul li div" ).hide();
}
});
I've been playing with this for a good two hours now using first-child
, .current
, :not
syntax and a variety of class combinations. I think it's safe to say that displaying the first div to begin with, then having it disappear when another is the :target
isn't possible with just pure CSS and HTML.
I got it to the point where the first question was display: block;
, and all the others were going on and off when another was active, however the first question was always active throughout.
So, in answer to your question:
No, I am 95% sure it is not possible with the markup above, as each div is in its own individual li
. I was hoping I could prove myself wrong, but I cannot. If someone else can achieve this then they'll certainly be getting an up-vote from me.
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