How to pass an URL to a <a href=“”>

Question

I'm still new to php and I've made a script that checks the language of the website and if it's English set's the button link to an english page and else to another page.

Here goes:

<?php 
                            $link1 = "http://www.uvt.ro/ro/accesibilitate/";
                            $link2 = "http://www.uvt.ro/en/accesibilitate/";
                            $url = "";
                            if($_SESSION["lang"]->lang!="ro"){
                                $url = $link2;
                            }
                            else {
                                $url = $link1;
                            }
                            ?>

<a href=".$url.">Button</a>

It's supposed to be simple, I don't know why it doesn't work.

Answer 1

You'd echo the $url like so:

<?php 
$link1 = "http://www.uvt.ro/ro/accesibilitate/";
$link2 = "http://www.uvt.ro/en/accesibilitate/";
$url = "";
if ($_SESSION["lang"]->lang != "ro") {
    $url = $link2;
}
else {
    $url = $link1;
}
?>

<a href="<?php echo $url;?>">Button</a>

You can condense the code to this using the ternary operator :

<?php 
$link1 = "http://www.uvt.ro/ro/accesibilitate/";
$link2 = "http://www.uvt.ro/en/accesibilitate/";
$url = ($_SESSION["lang"]->lang != "ro") ? $link2 : $link1;
?>

<a href="<?php echo $url;?>">Button</a>

Answer 2

你必须在标签中回显$ url。

<a href="<?php echo $url;?>">Button</a>

Answer 3

<a href=".$url.">Button</a>

replace with:

<a href="<?php echo $url; ?>">Button</a>

OR

<a href="<?=$url?>">Button</a>

Answer 4

you can try this one:

See the page

<?php  
    $test = $_GET['p'];
 ?>
 <a href="diffdir/<?php echo $test ?>">Test</a>

or

Try like

HTML in PHP :

echo "<a href='".$link_address."'>Link</a>";

Or even you can try like

echo "<a href='$link_address'>Link</a>";

Or you can use PHP in HTML like

PHP in HTML :

<a href="<?php echo $link_address;?>"> Link </a>