fourdigityear<-c("2003/7/15","2009/6/12")
我应该如何将4位数字的年份转换为2位数字的年份,以便最终得到类似“ 7/15/03”,“ 12/6/09”的信息。
First make your data into Date
s:
fdy <- as.Date(fourdigityear, format='%Y/%m/%d')
Then convert format
as.character(fdy, format = '%m/%d/%y')
# "07/15/03" "06/12/09"
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