Notification about task execution flask and celery

Question

I am using celery and flask with a mongodb backend and broker.
I am trying to understand whats the best way to give a notification after running a group of synchronous task.

Both of the function have a decorator called @celery.task

def abc():  
    # do something

def fgh():  
    # do something

In order to run these programs, I am using (abc.s() | fgh.s()).delay() to run these tasks.

How do I signal the main program once these tasks have been executed completely?

Answer 1

Mb u can try flask-notification with Redis as Celery backend. Another way: check task state/status (something like status = celery.AsyncResult(str(task_id)).status ) with waiting intervals time.sleep(10) in cycle (for example, while True: ... ) and update progress bar on some page with jquery. After task completion (SUCCESS or FAILED status) you can show message with flash('your message') or set redirect. Hope thats help.