The commented line below throws an error.
class Overall_Travel_Times_Widget extends WP_Widget {
var $title = 'Travel Times Widget';
//var $title_link = get_permalink( get_page_by_path( 'delays' ) );
How can I access the standard wordpress functionality from inside the widget definition?
I tested your code, it was outputting parse error "unexpected var"
Parse error: syntax error, unexpected 'var' (T_VAR)
I remove var keyword in front of your variables and it worked:
$title = 'Travel Times Widget';
$title_link = get_permalink( get_page_by_path( 'delays' ) );
So after removing 'var' which you have in front of both variables, your code will work fine. As I tested it provided me the link for the page with the slug I provided.
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