This is a two part question.
I have a data set that is 2x6 named Price.
I want to create a for loop that will multiply specific rows within Price by (1-h) and -1*(1-h). The results of this should fill a new matrix that is only 2x3.
The input of Price has values in the first column of rows 1-3, and values in the second column of rows 4-6. The other values are just zeros.
h <- .02
> Price
V1 V2
1 15.24 0.00
2 15.24 0.00
3 15.24 0.00
4 0.00 8.76
5 0.00 8.76
6 0.00 8.76
The new matrix should look as the following:
> effective.price
V1 V2
1 14.94 -8.58
2 15.24 -8.76
3 15.24 -8.76
I don't even know where to begin, any help would be greatly appreciated.
Thanks
I think that it's easier than you think. If you really have a fixed input like that, then
price <- read.table(text = "15.24 0.00
15.24 0.00
15.24 0.00
0.00 8.76
0.00 8.76
0.00 8.76")
newPrice <- as.data.frame(cbind(price$V1[1:3],price$V2[4:6]))
where you are using column binds over set sections of your columns. The first column takes the values of V1[1 to 3], etc.
Yields
> newPrice
V1 V2
1 15.24 8.76
2 15.24 8.76
3 15.24 8.76
If you need to change the value of the elements of newPrice
you can operate on that in a vector fashion:
newPrice$V1 <- newPrice$V1 * (1 - h)
newPrice$V2 <- newPrice$V2 * (h - 1)
yielding
> newPrice
V1 V2
1 14.9352 -8.5848
2 14.9352 -8.5848
3 14.9352 -8.5848
I'm not sure exactly what the h
is but I think this does what you want.
df <- read.table(text = "V1 V2
1 15.24 0.00
2 15.24 0.00
3 15.24 0.00
4 0.00 8.76
5 0.00 8.76
6 0.00 8.76")
h <- 0.02
df$V1 <- df$V1 * (1 - h)
df$V2 <- - df$V2 * (1 - h)
effective.price <- data.frame(lapply(df, function(x) x[x != 0]))
This gives:
V1 V2
1 14.9352 -8.5848
2 14.9352 -8.5848
3 14.9352 -8.5848
You can also do this with reshaping:
library(dplyr)
library(tidyr)
df %>%
mutate(V1 = V1 * (1-h),
V2 = V2 * -(1-h),
ID = n() %>% `/`(2) %>% seq %>% rep(2)) %>%
gather(variable, value, -ID) %>%
filter(value != 0) %>%
spread(variable, value)
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