php mysqli, how to select values and prepare them to update other tables

Question

I have a mysqli query with the following code:

    $stmt = $mysqli->prepare('SELECT `user`, `status` FROM `mytable1` WHERE `type`=?');
    $type = 1;
    $stmt->bind_param('i', $type);
    $stmt->execute();
    $stmt->bind_result($user, $status);
    $stmt->store_result();
    $stmt->fetch();
    $stmt->close();

And I need update column "Money" where users have type "1" from "mytable1"

$stmt = $mysqli->prepare('UPDATE `mytable2` SET `money`=100 WHERE `user`=?');
$stmt->bind_param('s', $user);
$stmt->execute();
$stmt->close();

In this way update only one user. I found PHP documentation but there is no example :(

Answer 1

Perhaps a combined query like this:

UPDATE `mytable2` SET `money`=100 WHERE `user` in (
SELECT distinct `user` FROM `mytable1` WHERE `type`=?'
);