JavaScript random order functions

Question

I have the following problem:

I want to call my functions func1() , func2() & func3() in a random order. But i want to be sure that every function is called!

If it's possible it also would be nice that no functions are used; just a random order of code sequences. Like this:

function xy(){

   //Call this sequence first second or third
   doSomething1

   //Call this sequence first second or third
   doSomething2

   //Call this sequence first second or third
   doSomething3

   //!! But call each sequence !!

}

Thanks in advance ;)

Answer 1

You could put all function names as strings into an Array, then sort this array randomly and call the functions:

var funcArr = new Array("func1", "func2", "func3");
shuffle(funcArr); //You would need a shuffle function for that. Can be easily found on the internet.

for (var i = 0; i < funcArr.length; i++)
    window[funcArr[i]]();

EDIT: If you don't want functions but lines of code to be sorted randomly, then that's not going to work. JavaScript does not have a goto command (at least not without an external API), so you can't jump between code lines. You can only mix functions, as shown above.

Answer 2

There is many ways to do that, one of the most easy way is like this:

Array.prototype.shuffle = function () {
  this.sort(function() { return 0.5 - Math.random() });
}

[func1, func2, func3].shuffle().forEach(function(func, index, array){
  func();
});

Answer 3

You can use something like the Fisher-Yates shuffle for shuffling the functions and then call them via Array.prototype.forEach() :

 var a = function () { alert('a'); }, b = function () { alert('b'); }, c = function () { alert('c'); }, array = [a, b, c]; array = array.map(function (a, i, o) { var j = (Math.random() * (o.length - i) | 0) + i, t = o[j]; o[j] = a; return t; }); array.forEach(function (a) { a(); });