How can i select the last value in a particular column in mysql database?

Question

I am currently using this query to fetch all the values from a table where the invoiceNo is distinct.

SELECT * FROM  `selected_items` WHERE invoiceNo IN ( SELECT DISTINCT ( invoiceNo) AS invoiceNo FROM selected_items ) GROUP BY invoiceNo;

This is my table structure

And I would like to access everything from the last row.My current query gives me the first row.Thank you :)

Answer 1

use order by rownum or GROUP BY

Select * From (
SELECT t.*, 
       @rownum := @rownum + 1 AS rank
  FROM selected_items t, 
       (SELECT @rownum := 0) r order by rank DESC
) si GROUP BY si.invoiceNo

Answer 2

试一试

SELECT * FROM selected_items WHERE invoiceNo IN ( SELECT DISTINCT ( invoiceNo) AS invoiceNo FROM selected_items ) GROUP BY invoiceNo ORDER BY custInfo DESC LIMIT 1;

Answer 3

您应该使用ORDER BY列名，这样您将首先获得最后一个条目

SELECT * FROM  `selected_items` WHERE invoiceNo IN ( SELECT DISTINCT ( invoiceNo) AS invoiceNo FROM selected_items ) GROUP BY invoiceNo ORDER BY invoiceNo DESC LIMIT 1;

Answer 4

Is it?:

SELECT DISTINCT invoiceNo, barcode, description, weight, rate, makingAmt, net_rate, itemTotal, vat 
FROM selected_items 
GROUP BY invoiceNo 
ORDER BY date DESC LIMIT 1;

to get last row there should some fields that contains unique values.

Answer 5

If you want to get the highest sum_total of each invoiceNo then you can do something like this,

SELECT invoiceNo, MAX(sum_total) AS sumTotal
FROM selected_items 
GROUP BY invoiceNo;