I have a form in which i am trying to auto populate the value of radio button.
content=content+' <label class="radio-inline">';
content=content+' <input type="radio" name="ip_radio_resp_'+questDetail.qId+'" id="radioYes" value="Y" onclick="removeFocusOnComment('+questDetail.qId+');showReasonTextBox('+questDetail.qId+')"> Yes';
content=content+' </label>
I am checking for value for some other field, if I get the desired response I marked radio btn else not
switch(questDetail.metricsValue){
case 'Y':
$('#ip_radio_resp_'+questDetail.qId).each(function() {
$('input:radio[name="ip_radio_resp_'+questDetail.qId+'"]#radioYes').prop('checked',true);
});
break;
case 'N' :
//something......
break;
default:
//something
}
I am using jquery 1.11.2
But it constantly given me error undefined..I know this can be a duplicate and I tried all other answers given, but not able to get this working...can someone please help!!
Thanks in advance.
You can't have id="radioYes"
in every radio group, because IDs must be unique. Use class="radioYes"
instead. Then you can do:
case 'Y':
$('input:radio[name="ip_radio_resp_'+questDetail.qId+'"].radioYes').prop('checked',true);
break;
You don't need to use $('#ip_radio_resp_'+questDetail.qId).each
because you're not doing anything with the element with that ID (I suspect you don't even have that element, and you were confusing name
with id
).
i think you don't need all that, you just need to check while you making you radio buttons if the
questDetail.metricsValue == 'Y'
then you need to make it checked.
you can cancel all of you switch case you create and make it this way it will be easier for you.
content=content+' <label class="radio-inline">';
content=content+' <input type="radio" name="ip_radio_resp_'+questDetail.qId+'" class="radiosToBeChecked" id="radioYes'+questDetail.qId+'" checked="'+(questDetail.metricsValue == 'Y') ? 'checked': ''+'" onclick="removeFocusOnComment('+questDetail.qId+');showReasonTextBox('+questDetail.qId+')"> Yes';
content=content+' </label>';
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