I have this drop down list that when I click on it, it shows me a hidden div
<form action="" method="post" name="select_name_form">
<input type="submit" name="select_name_submit" value="debts"/>
<select onchange="showMe(this);" name="select_name">
<?php foreach($result1 as $name) { ?>
<option value="<?php echo $name['name'] ?>"><?php echo $name['name'] ?></option>
<?php } ?>
</select>
</form>
And this is the javascript code:
<script type="text/javascript">
function showMe(e) {
var strdisplay = e.options[e.selectedIndex].value;
var e = document.getElementById("section3");
if(strdisplay == "Hide") {
e.style.display = "none";
} else {
e.style.display = "block";
}
}
</script>
What I want to make when I click on any value of this list is still shows me the hidden div but I want to apply this PHP code and select data into that div:
if(isset($_POST['select_name_submit'])){
$name_selected = $_POST['select_name'];
try{
$query = ("SELECT * FROM debts WHERE name=:name");
$stmt = $conn->prepare($query);
$stmt->bindValue(":name", $name_selected);
$count = $stmt->execute();
//header("location: debts.php");
}
catch(PDOException $e) {
echo $e->getMessage();
header("location: debts.php");
}
}
This PHP code is in the same page where I have the drop down list. So how can I make the drop list run 2 code when a name is selected from it (one code is JS and the second is PHP).
The scenario which you mentioned can be achieved using ajax,
http://www.w3schools.com/php/php_ajax_database.asp
Please refer this example, you will get more idea.
in case needed, please add comment, i can help you.
Thanks Amit
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