Express.js: How to serve one file for the default “/” route, then use express.static for the rest?

Question

I have a basic express app and I want to serve one file (after performing some logic) for the default route of / .

Unfortunately I can't use

app.use(function (res, res, next){
    *logic here*
    res.sendFile(filepath);
}); 

express.static()

because that will intercept every request and send the filepath for every request.

Is there another way of doing this?

Answer 1

It's enough to check the URI part of url and if it's / then send file.

Check this:

app.use(function (req, res, next) { // first must be Your middleware
  if(req.path == '/') {
    return res.sendFile('some file');
  }

  next();
}); 

app.use(express.static('public'));  // and after it You can attach static middleware

or:

app.use(express.static('public'));

app.all('/', function (req, res) {
  res.sendFile(filePath);
});

Answer 2

var regexp = /^\/\w+/





app.use(function (req, res, next){
  if(!regexp.test(req.path)){
    res.sendFile(filepath);
 }  

}); 

express.static()

this may work comment your requirement