I'm a beginner in developing, so my sensei gave me a task to complete in which I need to enter a couple of strings in linked lists and after I enter print, they need to be printed in the correct order, from the first to last.
Here is what I got:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct Node {
char data;
struct Node *next;
}node;
char createlist(node *pointer, char data[100]) {
while (pointer->next != NULL) {
pointer = pointer->next;
}
pointer->next = (node*) malloc(sizeof(node));
pointer = pointer-> next;
pointer->data = *data;
pointer->next = NULL;
}
int main() {
node *first, *temp;
first = (node*) malloc(sizeof(node));
temp = first;
temp->next = NULL;
printf("Enter the lines\n");
while (1) {
char data[100];
gets(data);
createlist(first, data);
if (strcmp(data, "print") == 0)
printf("%s\n", first->data);
else if (strcmp(data, "quit") == 0)
return (0);
};
}
When I run it I get: Enter the lines: asdfasdf print (null)
Any help would be appreciated since this is my first time using linked lists.
first->data
is allocated via malloc()
and isn't initialized, so using its value invokes undefined behavior . createlist()
modify first
. createlist()
won't return anything, type of its return value should be void
. gets()
, which has unavoidable risk of buffer overrun. free()
whatever you allocated via malloc()
. improved code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct Node
{
char *data;
struct Node *next;
} node;
void createlist(node **pointer, char data[100])
{
while (*pointer != NULL)
{
pointer = &(*pointer)->next;
}
*pointer = malloc(sizeof(node));
if (*pointer == NULL)
{
perror("malloc 1");
exit(1);
}
(*pointer)->data = malloc(strlen(data) + 1);
if ((*pointer)->data == NULL)
{
perror("malloc 2");
exit(1);
}
strcpy((*pointer)->data, data);
(*pointer)->next = NULL;
}
int main(void)
{
node *first = NULL;
printf("Enter the lines\n");
while (1)
{
char data[100], *lf;
if (fgets(data, sizeof(data), stdin) == NULL) strcpy(data, "quit");
if ((lf = strchr(data, '\n')) != NULL) *lf = '\0'; /* remove newline character */
createlist(&first, data);
if (strcmp(data, "print") == 0)
{
node *elem = first;
while (elem != NULL)
{
printf("%s\n", elem -> data);
elem = elem->next;
}
}
else if (strcmp(data, "quit") == 0)
{
while (first != NULL)
{
node *next = first->next;
free(first->data);
free(first);
first = next;
}
return(0);
}
}
}
Inside createlist()
, you are iterating to the end of the list. There, you are adding a new node and setting a new text entered. By doing so, you are missing that you have already a first node. Because you are iterating to the end in every call of createlist()
, you are jumping over your first node every time, so it remains without text and delivers NULL
.
In order not to jump over the first initial node, you could alter createlist()
like this:
char createlist(node *pointer, char data[100])
{
while (pointer->data != NULL && pointer->next != NULL)
{
pointer = pointer->next;
}
...
...
}
Or you could create the first node not initially, but only after the first line of text was entered.
edit : Here are two additional style hints:
What happens if somebody enters 120 characters? The text will outrun your char[100]
array and will fill RAM that is used otherwise. This is a buffer overflow. You could try to grab only the first 100 chars, get the substring . Alternatively, use the length argument of fgets()
Create a constant for 100, like #define MAX_BUFFER_LENGTH 100
, and use it every time.
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