Well, I have this script over here, when I click on it, It should delete from database and then slideUp the div I deleted, but it isn't working.
<div id="warn">
<a data-aviso="<?=$warns['id']; ?>" id="click" style="float: right;">
<i class="fa fa-times"></i>
</a>
$(document).on("click", "#click", function() {
$.ajax({
type: "POST",
url: "delete.php",
data: "id=" + id,
cache: false,
success: function(g) {
if (g == "1") {
$("#warn").slideUp("slow");
}
}
});
});
warn
is the id of the div
I want to slideUp. Also, it only slideUp the first one I click, the rest of them don't move.
UPDATE: This seems to work I just gave the div warn a new id:
<div id="warn<?=$warns['id']; ?>">
And in the script I just did this:
$(document).on("click", "#click", function(){
var id = $(this).attr('data-aviso');
$.ajax({
type: "POST",
url: "delete.php",
data: "id="+id,
cache: false,
success:function(g){
if(g == "1"){
$('#este'+id).slideUp("slow");
}
}
});
});
I believe you mean this:
id
to class
data
attributeLike this
<div class="warn">
<a data-aviso="<?=$warns['id']; ?>" class="click" style="float: right;">
<i class="fa fa-times"></i>
</a>
using
$(document).on("click", ".click", function(e) {
e.preventDefault(); // stop default action of link
var $link = $(this);
var id = $link.data("aviso");
$.ajax({
type: "POST",
url: "delete.php",
data: "id=" + id,
cache: false,
success: function(g) {
if (g == "1") {
$link.closest("div.warn").slideUp("slow");
}
}
});
});
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.