OR function in if (trim() == "") {}
in PHP?
tried this, not work:
if (trim($query) == "a" or "b") {$search= 'd'; }
I want if either a or b exist d goes to $search
Learn PHP the right way from PHP Manual . It should be:
if (trim($query) == "a" || trim($query) == "b") {
$search= 'd';
}
Or you can use in_array
:
if (in_array(trim($query), array('a', 'b'))) {
$search = 'd';
}
If you wanna look for partial ones, then you can do:
if (strpos("a", trim($query)) > -1 || strpos("b", trim($query)) > -1) {
In your conditional, you must use the if statement 2x with or
or ||
operator, like this:
if (trim($query) == "a" or trim($query) == "b") {$search= 'd'; }
You can also use this:
if (trim($query) == "a" || trim($query) == "b") {$search= 'd'; }
Of course, you can also use in_array()
function in your statement:
if (in_array(trim($query), array('a', 'b'))) {
$search = 'd';
}
if( in_array( trim($query), array('a', 'b') ) ) {
$search = 'd';
}
Easy peasy
if (trim($query) == "a" or trim($query) == "b"){
// Do somenthing
}
First of all, you probably should not use the or
operator, since it has a very weird precedence. Use ||
instead.
http://php.net/manual/en/language.operators.logical.php
Second, you need to compare the result of trim twice. or
is a simple logical operator that evaluates boolean expressions and returns a bool, it won't magically make two comparisons happen.
$query = trim(query);
if ($query === 'a' || $query === 'b') { $search = 'd'; }
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