I'm looking for a solution to search keys in a dictionary according to a list as value, and later append the keys to a list of tuples. I'm able to search for the correct keys but can't find a way to build the list I'm expecting. Appreciate for kind help.
As below, I'd like to find all keys in d
which has a value equals to the element in the list l
, and further put all searched keys into a list of tuples as shown in expected output.
d = {'acutrar': 'acutrar',
'aguosa': 'aguoso',
'capitalizareis': 'capitalizar',
'conocerán': 'conocer',
'conociéremos': 'conocer',
'conocían': 'conocer',
'conocías': 'conocer',
'conozcas': 'conocer',
'pales': 'palar',
'planeareis': 'planear',
'planearás': 'planear',
'planeasteis': 'planear',
'planeáramos': 'planear'}
l = ['conocer', 'NOT FOUND', 'NOT FOUND', 'planear']
for word in l:
for (x,y) in d.items():
if y == word:
print(word, x) #I can only search for the keys but don't know how to build that list of tuples
Expected Output:
[('conocerán','conocías','conozcas','conocían','conociéremos'),('NOT FOUND'),('NOT FOUND'),('planeáramos','planeareis','planearás','planeasteis')]
Why don't transform the dictionary into a more suitable/convenient structure and perform the O(1) lookups by key instead of looping over all of the items and searching for the value:
from collections import defaultdict
d = {'acutrar': 'acutrar',
'aguosa': 'aguoso',
'capitalizareis': 'capitalizar',
'conocerán': 'conocer',
'conociéremos': 'conocer',
'conocían': 'conocer',
'conocías': 'conocer',
'conozcas': 'conocer',
'pales': 'palar',
'planeareis': 'planear',
'planearás': 'planear',
'planeasteis': 'planear',
'planeáramos': 'planear'}
t = defaultdict(list)
for key, value in d.items():
t[value].append(key)
l = ['conocer', 'NOT FOUND', 'NOT FOUND', 'planear']
print([t.get(item, [item]) for item in l])
Prints:
[
['conozcas', 'conociéremos', 'conocías', 'conocerán', 'conocían'],
['NOT FOUND'],
['NOT FOUND'],
['planeáramos', 'planearás', 'planeareis', 'planeasteis']
]
Your result is surprisingly a blend of keys and values.
A more homogeneous solution can be obtained by
[tuple(k for (k,v) in d.items() if v == w) for w in l]
for
[('conocías', 'conozcas', 'conociéremos', 'conocerán', 'conocían'),
(),
(),
('planeareis', 'planeáramos', 'planeasteis', 'planearás')]
or :
{w:tuple(k for (k,v) in d.items() if v == w) for w in l}
for
{'conocer': ('conocías', 'conozcas', 'conociéremos', 'conocerán', 'conocían'),
'NOT FOUND': (),
'planear': ('planeareis', 'planeáramos', 'planeasteis', 'planearás')}
To get your expected output, you can build the list of tuples like this:
for word in l:
hits = tuple()
for (x,y) in d.items():
if y == word:
hits += (x,)
if not hits:
hits = ('NOT FOUND',)
results.append(hits)
print(results)
First no need to iterate on the list of searched values IMO.
You could just do:
final = []
for k, v in d.items():
if v in l:
final.append(k)
final = tuple(final)
But you could even simplify it via a list comprehension as below:
final = tuple(k for k, v in d.items() if v in l)
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