Shell script cp not working (but working in terminal) Mac os X

Question

I've been recently learning about shell scripting, and am stumped by a weird error:

My simple script (test.command):

#!/bin/sh
clear
cd /Users/Stan/Desktop/testFolder
ls 
cp "earth.png lol.png"
read -p "Done, press ENTER to finish"

Whenever I run the script (double clicking the .command file), here is the output (copied from terminal window):

earth.png
usage: cp [-R [-H | -L | -P]] [-fi | -n] [-apvX] source_file target_file
       cp [-R [-H | -L | -P]] [-fi | -n] [-apvX] source_file ... target_directory
Copy was done...?
earth.png
Done, press ENTER to finish

The cp ALWAYS gives a 'usage' error, and WONT copy anything, but now if i manually run the SAME exact commands, in order in terminal (copy of terminal window):

Stans-Mac-mini:testFolder Stan$ ls
earth.png
Stans-Mac-mini:testFolder Stan$ cp earth.png lol.png
Stans-Mac-mini:testFolder Stan$ ls
earth.png   lol.png
Stans-Mac-mini:testFolder Stan$ 

The file got copied without any error! Please help me fix this, I couldn't find any solutions online, help is greatly appreciated!

Answer 1

Change cp command

cp "earth.png" "lol.png"

cp command format is : cp <from> <to> . Your command has it like cp "<single-file>" . Both earth.png and lol.png are within the quotes and that makes it a single file. Second argument is missing and thats the reason for "usage error"

Answer 2

When you quote both the source and the destination arguments provided to cp as one string, it only gets the one argument.
The command:

cp "earth.png lol.png"

attempts to copy one file with the name "earth.png lol.png" (which by the way is a perfectly valid file name), but then fails to provide a second argument.
Instead, quote each individual argument:

cp "earth.png" "lol.png"