I have a large pandas dataframe of time-series data.
I currently manipulate this dataframe to create a new, smaller dataframe that is rolling average of every 10 rows. ie a rolling window technique. Like this:
def create_new_df(df):
features = []
x = df['X'].astype(float)
i = x.index.values
time_sequence = [i] * 10
idx = np.array(time_sequence).T.flatten()[:len(x)]
x = x.groupby(idx).mean()
x.name = 'X'
features.append(x)
new_df = pd.concat(features, axis=1)
return new_df
Code to test:
columns = ['X']
df_ = pd.DataFrame(columns=columns)
df_ = df_.fillna(0) # with 0s rather than NaNs
data = np.array([np.arange(20)]*1).T
df = pd.DataFrame(data, columns=columns)
test = create_new_df(df)
print test
Output:
X
0 4.5
1 14.5
However, I want the function to make the new dataframe using a sliding window with a 50% overlap
So the output would look like this:
X
0 4.5
1 9.5
2 14.5
How can I do this?
Here's what I've tried:
from itertools import tee, izip
def window(iterable, size):
iters = tee(iterable, size)
for i in xrange(1, size):
for each in iters[i:]:
next(each, None)
return izip(*iters)
for each in window(df, 20):
print list(each) # doesn't have the desired sliding window effect
Some might also suggest using the pandas rolling_mean() methods, but if so, I can't see how to use this function with window overlap.
Any help would be much appreciated.
I think pandas rolling techniques are fine here. Note that starting with version 0.18.0 of pandas, you would use rolling().mean()
instead of rolling_mean()
.
>>> df=pd.DataFrame({ 'x':range(30) })
>>> df = df.rolling(10).mean() # version 0.18.0 syntax
>>> df[4::5] # take every 5th row
x
4 NaN
9 4.5
14 9.5
19 14.5
24 19.5
29 24.5
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