I am getting list of images from a folder for particular ID. Right now I am getting file names but I also want to get upload path.
How to get both data in one function.
Jquery Code:
listFilesOnServer(project_id);
function listFilesOnServer (project_id) {
var items = [];
uploadURI = uploadURI+'/'+project_id;
console.log(project_id+'--KAL--'+uploadURI);
$.getJSON(uploadURI ,function(data,path) {
console.log(data);
$('div #list-group').html("").html(items.join(""));
});
}
Controller Code:
function listFiles() {
$this->load->helper('file');
$project_id = $this->uri->segment(3);
$builders_id = $this->admin_model->getBuilderID($project_id);
$UPLD_PATH = $this->admin_model->builder_UPLD_PATH($builders_id);
$upload_path = "./application/assets/images/" . $UPLD_PATH;
$files = get_filenames($upload_path);
echo json_encode($files);
}
You should modify your controller action so that it returns an json_encode(array('files'=>$yourFiles, 'filePath'=>$yourFilePath) );
like below :
function listFiles() {
$this->load->helper('file');
$project_id = $this->uri->segment(3);
$builders_id = $this->admin_model->getBuilderID($project_id);
$UPLD_PATH = $this->admin_model->builder_UPLD_PATH($builders_id);
$upload_path = "./application/assets/images/" . $UPLD_PATH;
$files = get_filenames($upload_path);
echo json_encode(array('files'=>$files, 'uploadPath'=>$upload_path) );
exit();
}
Then modify your jquery code to handle the json response and extract the response like below :
listFilesOnServer(project_id);
function listFilesOnServer (project_id) {
var items = [];
uploadURI = uploadURI+'/'+project_id;
console.log(project_id+'--KAL--'+uploadURI);
$.getJSON(uploadURI ,function(data,path) {
//Your upload path
console.info("UPLOAD PATH: "+data.uploadPath);
//Your files
console.log(data.files);
//Your processing logic goes here
$('div #list-group').html("").html(items.join(""));
});
}
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.