I have this code that attempts to go to a URL and parse 'li' elements into an array. However I have run into a problem when trying to parse anything that is not in a 'b' tag.
Code:
url = '(some URL)'
page = Nokogiri::HTML(open(url))
csv = CSV.open("/tmp/output.csv", 'w')
page.search('//li[not(@id) and not(@class)]').each do |row|
arr = []
row.search('b').each do |cell|
arr << cell.text
end
csv << arr
pp arr
end
HTML:
<li><b>The Company Name</b><br>
The Street<br>
The City,
The State
The Zipcode<br><br>
</li>
I would like to parse all of the elements so that the output would be something like this:
["The Company Name", "The Street", "The City", "The State", "The Zip Code"],
["The Company Name", "The Street", "The City", "The State", "The Zip Code"],
["The Company Name", "The Street", "The City", "The State", "The Zip Code"]
require 'nokogiri'
def main
output = []
page = File.open("parse.html") {|f| Nokogiri::HTML(f)}
page.search("//li[not(@id) and not (@class)]").each do |row|
arr = []
result = row.text
result.each_line { |l|
if l.strip.length > 0
arr << l.strip
end
}
output << arr
end
print output
end
if __FILE__ == $PROGRAM_NAME
main()
end
I ended up finding the solution to my own question so if anyone is interested I simply changed
row.search('b').each do |cell|
into:
row.search('text()'.each do |cell|
I also changed
arr << cell.text
into:
arr << cell.text.gsub("\n", '').gsub("\r", '')
in order to remove all the \\n and the \\r that were present in the output.
Based on your HTML I'd do it like:
require 'nokogiri'
doc = Nokogiri::HTML(<<EOT)
<ol>
<li><b>The Company Name</b><br>
The Street<br>
The City,
The State
The Zipcode<br><br>
</li>
<li><b>The Company Name</b><br>
The Street<br>
The City,
The State
The Zipcode<br><br>
</li>
</ol>
EOT
doc.search('li').map{ |li|
text = li.text.split("\n").map(&:strip)
}
# => [["The Company Name",
# "The Street",
# "The City,",
# "The State",
# "The Zipcode"],
# ["The Company Name",
# "The Street",
# "The City,",
# "The State",
# "The Zipcode"]]
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