I want to hide rows 7 through X in Excel, where X is the row 6 rows above the first instance of a value in column A.
Google seems to come up with things that look WAY WAY too complicated for my purposes.
What I have so far is a basic:
'Select Rows 7 through 3 rows before the first instance of any text in column A, then hides them
Rows("7:62").Select
' have to update the 62 above to look for text and hide based on that
Selection.Rows.Group
Selection.EntireRow.Hidden = True
within my Sub. I just need to figure out how to change the 62 to be a variable cell that is usually around the 60's, but is not always the exact value of 62.
Try to avoid using Select
when possible.
strValueToFind = "What ever the value you are trying to find in column A is"
With Sheets("Sheet1")
'Find the row containing the value
intFoundRow = .Range("A:A").Find(What:= strValueToFind, _
LookIn:=xlValues, _
LookAt:=xlWhole).Row
'Now hide Rows 7 through 6 above the row we found
.Rows("7:" & intFoundRow - 6).Hidden = True
End With
Hopefully that's not too complicated. :)
Your narrative says 'row 6 rows above' and your code says '3 rows before' . I usually believe the code. This is important due to the maths involved and ensuring that you are not trying to hide rows above row 7.
Dim rw As Variant
rw = Application.Match(Chr(42), Range("A8:A1048576"), 0)
If Not IsError(rw) Then
rw = Application.Max(rw + 4, 7)
Range("A7:A" & rw).EntireRow.Hidden = True
End If
Say we start with:
and we want to hide all rows 7 through 6 rows above the first occurrence of "happiness". Running this:
Sub FindAndHide()
Dim rng As Range
Set rng = Range("A:A")
Range(Cells(7, 1), rng.Find(What:="happiness", after:=rng(7)).Offset(-6, 0)).EntireRow.Hidden = True
End Sub
will produce:
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