C# CodeDom generic add “out” parameter

Question

I like to create a funktion which has a generic parameter:

public interface IInterfaceMethod< out T0> : where T0 : IInterface2

So i created a new CodeTypeParameter and added this as constraint. So how can i create the "out" value?

Thanks

Answer 1

You can only put the T0 generic type in "out" positions inside this interface:

• As the data type of a getter-only property
• As the data type of the return value of a method

You can not:

• Use the type as the data type for a property with a setter
• Use the type as the data type for a parameter (not even out parameters)

So this is an example of your interface:

public interface IInterfaceMethod<out T0>
    where T0 : IInterface2
{
    T0 GetterOnly { get; }
    T0 MethodReturnValue();
}

while this is illegal:

public interface IInterfaceMethod<out T0>
    where T0 : IInterface2
{
    T0 GetterAndSetter { get; set; }
    void MethodParameter(T0 value);
    void MethodOutParameter(out T0 value);
}