I am trying to insert multiple images in database. On submit, i am getting only one image details in $_FILES[]. Why the other submitted images are not displaying in array?
Also, upload.php has error saying Array to string conversion in C:\\xampp\\htdocs\\kabootar\\upload.php on line 15 that is
$targetFile = $targetDir.$fileName;
How can i solve these problems?
html
<form action="upload.php" method="post" enctype="multipart/form-data">
<input type="submit" value="Upload" name="upload">
<label class="add">Select more..</label>
<div class="prep">
<div class="col-md-4">
<img src="http://png-4.findicons.com/files/icons/129/soft_scraps/256/button_upload_01.png" id="upfile1" style="cursor:pointer" class="img" />
<input type="file" class="inputimg" name="multiple_uploaded_files[]" />
</div>
</div>
</form>
javascript
<script type="text/javascript">
$(document).on("click", ".img", function () {
$(this).closest("div").find(".inputimg").trigger("click");
});
var count = 1;
$(".add").on("click", function () {
count++;
if(count <= 5){
var row = '<div class="col-md-4"> <img src="http://png-4.findicons.com/files/icons/129/soft_scraps/256/button_upload_01.png" id="upfile1" style="cursor:pointer" class="img"/ ><input type="file" class="inputimg" />\n\
';
$(".prep").append(row);
$(".inputimg").change(function () {
console.log(this);
readURL(this);
});
}else{
alert('You are only allowed to add uptp 5 images');
}
});
$(".inputimg").change(function () {
readURL(this);
});
function readURL(input) {
if (input.files && input.files[0]) {
var reader = new FileReader();
reader.onload = function (e) {
$(input).siblings('.img').attr('src', e.target.result);
}
reader.readAsDataURL(input.files[0]);
}
}
</script>
upload.php
if(isset($_POST['upload']))
{
if(!empty($_FILES)){
foreach ($_FILES['multiple_uploaded_files']['name'] as $file)
{
$targetDir = "upload/";
$fileName = $_FILES['multiple_uploaded_files']['name'];
$targetFile = $targetDir.$fileName;
//use the move_uploaded_file() to move your file on your server directory.
if(move_uploaded_file($_FILES['multiple_uploaded_files']['tmp_name'][$file], $targetFile))
{
//insert file information into db table
$sql = mysqli_query($link,"INSERT INTO files (file_name, uploaded) VALUES('".$fileName."','".date("Y-m-d H:i:s")."')");
echo 'file inserted';
}
else
{
echo 'Query not working';
}
}
//fire an insert query that inserts all the file names with comma separated value
}
else
{
echo 'No file selected';
}
You are trying to concat string with array $_FILES['multiple_uploaded_files']['name']. For Array to string conversion error
replace the code
$fileName = $_FILES['multiple_uploaded_files']['name'];
with
$fileName = $file; (or)
$fileName = $_FILES['multiple_uploaded_files']['name'][0];
Single file upload issue. You have not added name attribute for the input tag in javascript code.
replace
var row = '<div class="col-md-4"> <img src="http://png-4.findicons.com/files/icons/129/soft_scraps/256/button_upload_01.png" id="upfile1" style="cursor:pointer" class="img"/ ><input type="file" class="inputimg" />\n\';
With
var row = '<div class="col-md-4"> <img src="http://png-4.findicons.com/files/icons/129/soft_scraps/256/button_upload_01.png" id="upfile1" style="cursor:pointer" class="img"/ ><input type="file" class="inputimg" name="multiple_uploaded_files[]"/>\n\';
Note: added name attribute to the input tag.
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