what happen to return statement in catch block

Question

I have tried this code in javascript

function abc(){
  try{
     console.log(0);
     throw "is empty";}
  catch(err){
     console.log(1);
     return true;
  }
  finally{return false;}
  return(4);
}
console.log(abc()); 

I got output as false. I understand Finally always execute regardless of result of try catch but what happen to return statement in catch .

Answer 1

I understand Finally always execute regardless of result of try catch but what happen to return statement in catch .

Return statement in catch will be executed only if the catch block is reached, ie if there is an error thrown.

For example

function example() { 
    try { 
        throw new Error()
        return 1;
    } 
    catch(e) {
        return 2;
    }
    finally { 
    } 
} 

example() will return 2 since an error was thrown before return 1 .

But if there is a finally block and this finally block has a return statement then this return will override catch return statement.

For example

function example() { 
    try { 
        throw new Error()
        return 1;
    } 
    catch(e) {
        return 2;
    }
    finally { 
        return 3;
    } 
} 

Now example() will return 3 .

In your example, there is a return statement after the finally block. That statement will never get executed.

Try

function example() { 
    try { 
        throw new Error()
        return 1;
    } 
    catch(e) {
        return 2;
    }
    finally { 
        return 3;
    } 
   console.log(5)
   return 4;
} 

It only outputs 3 , 5 is never printed since after finally block value is returned.

Answer 2

Finally its always executed the last. So it overrides any other return you have. Therefore, your method returns false