I need to insert a value got from a document.getElementById into a sql query. I need to do this because i'm trying to autofill a second input box depending on the result of the first (ie if i type Rome in the first one i would like the second one to autofill with the related country found in my db, like Italy)
Here is the code:
<?php
echo (" <form NAME='Form1' id='Form1' method=post class=statsform action=page.php > " );
echo (" <input type=text name=city id=city size=50 class=formfield value='$city' onBlur='Assigncode();' > " );
echo (" <input type=text name='Country' id='Country' size=12 value='$Country' > " );
?>
<script>
function Assigncode() {
var elemento = document.getElementById("city");
var elementoCod = document.getElementById("Country");
if (elemento != null && elemento.value != '') {
var city = elemento.value;
if (elementoCod == null || elementoCod.value == '') {
<?php
$query2 = "SELECT * FROM table WHERE city = 'put here the getElementById of the city' ";
$result2 = MYSQL_QUERY($query2);
$i2 = 0;
$country = mysql_result($result2,0,"T_Country");
?>
eval( "document.Form1. Country").value = '<?php echo($country)?>';
}
}
}
</script>
Any suggestion? Thanks
Here is a slightly modified version of an AJAX example script found on Wikipedia. It should give you the basic idea on how to proceed. If you use jQuery then a lot of this JavaScript could be reduced to just a few lines.
// This is the client-side javascript script. You will need a second PHP script
// which just returns the value you want.
// Initialize the Http request.
var xhr = new XMLHttpRequest();
xhr.open('get', 'send-ajax-data.php?city=' + elemento.value);
// Track the state changes of the request.
xhr.onreadystatechange = function () {
var DONE = 4; // readyState 4 means the request is done.
var OK = 200; // status 200 is a successful return.
if (xhr.readyState === DONE) {
if (xhr.status === OK) {
document.Form1.Country.value = xhr.responseText; // 'This is the returned text.'
} else {
alert('Error: ' + xhr.status); // An error occurred during the request.
}
}
};
// Send the request to send-ajax-data.php
xhr.send(null);
send-ajax-data.php:
<?php
$city = $_GET['city'];
$query2 = "SELECT * FROM table WHERE city = '$city'";
$result2 = MYSQL_QUERY($query2);
$country = mysql_result($result2,0,"T_Country");
echo $country;
By the way, the $city variable should be validated and escaped prior to using it in an SQL query.
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