I have an XML document and I want to replace some special substrings using XSLT 1.0. I can't use the replace function (it's only available for XSLT 2.0). For this reason I found an alternative solution (the template string-replace-all ) and I'm trying to use it... but with no success. This is an example of XML:
<parent>
<child1>hello world!</child1>
<child2>example of text</child2>
</parent>
I want to replace "world" with "guys". I have this xslt
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions" xmlns="urn:hl7-org:v2xml" xmlns:hl7="urn:hl7-org:v2xml" exclude-result-prefixes="hl7">
<xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
<!--Identity template, copia tutto in uscita -->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template name="string-replace-all">
<xsl:param name="text" />
<xsl:param name="replace" />
<xsl:param name="by" />
<xsl:choose>
<xsl:when test="$text = '' or $replace = '' or not($replace)" >
<!-- Prevent this routine from hanging -->
<xsl:value-of select="$text" />
</xsl:when>
<xsl:when test="contains($text, $replace)">
<xsl:value-of select="substring-before($text,$replace)" />
<xsl:value-of select="$by" />
<xsl:call-template name="string-replace-all">
<xsl:with-param name="text" select="substring-after($text,$replace)" />
<xsl:with-param name="replace" select="$replace" />
<xsl:with-param name="by" select="$by" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$text" />
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template match="text()" >
<xsl:variable name="newtext">
<xsl:call-template name="string-replace-all">
<xsl:with-param name="text" select="." />
<xsl:with-param name="replace" select="world" />
<xsl:with-param name="by" select="guys" />
</xsl:call-template>
</xsl:variable>
</xsl:template>
</xsl:stylesheet>
The output is
<parent>
<child1/>
<child2/>
</parent>
The result of the call to string-replace-all
is set into the variable newtext
which is never used.
Just remove <xsl:variable name="newtext">
and </xsl:variable>
from the template match="text()"
.
And also look at the answer from @hr_117: If you want to replace the string world
by guys
you have to put them into '
. Otherwise an element world
is searched.
For example:
<xsl:template match="text()" >
<xsl:call-template name="string-replace-all">
<xsl:with-param name="text" select="." />
<xsl:with-param name="replace" select="'world'" />
<xsl:with-param name="by" select="'guys'" />
</xsl:call-template>
</xsl:template>
You need to change the template parameter to strings.
Try:
<xsl:call-template name="string-replace-all">
<xsl:with-param name="text" select="." />
<xsl:with-param name="replace" select="'a'" />
<xsl:with-param name="by" select="'A'" />
</xsl:call-template>
The select without the single quotation select="a"
is looking for an element a
.
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