How to get next node to be iterated in an XSLT for-each loop?

Question

If I have a for each loop such as:

<xsl:for-each select="$pChildren">
    <xsl:variable name="vNext" select="???" />
</xsl:for-each>

I am trying to assign the next node to be iterated in the for-each loop to vNext , if any.

I tried $pChildren[position()+1] but did not work.

Answer 1

I would prefer to answer this while seeing the entire context, but I believe:

<xsl:for-each select="$pChildren">
    <xsl:variable name="i" select="position()" />
    <xsl:variable name="vNext" select="$pChildren[$i + 1]" />
</xsl:for-each>

should work for you.

Answer 2

If you want to reference the next item in a sequence, you probably shouldn't be using a xsl:for-each statement in the first place. Reverse the order of the nodes and use xsl:iterate (unless you are making major use of multi-threading).

A more natural way to do this is:

<xsl:iterate select="reverse($pchildren)">
<xsl:param name="last" select="()"/>

Do Stuff Here using $last to reference the item that comes next in $pchildren.
<xsl:next-iteration>
<xsl:with-param name="last" select="."/>
</xsl:next-iteration>
</xsl:iterate/>