Playing around a coffeescript. I have the following for loop to concat a html element in native javascript which works well. At the moment I just couldnt get the value json data ie ia , ib from coffeescript.
//.js file
function createTr(json){
var tr='';
for (var i=0;i<json.data.length;i++){
var data ='<tr><td>' + json.data[i].a + ' - ' + json.data[i].b +
'</td>'+
'<td>' + json.data[i].c +
'</td>'+
'<td>' + json.data[i].d +
'</td>'+
'</tr>';
tr +=data;
}
return tr;
}
The coffescript is per below
//.coffeescript
createTr = (json) ->
tr=''
tr + '<tr><td>' + i.a + '-' + i.b+'</td> <td>'+i.c+'</td><td>'+i.d+'</td></tr>' for i in json.data
tr
the source map for the autogenerated javascript from the coffeescript as per below
//autogenerated js file from coffeescript file above
createTr = function(json) {
var i, j, len, ref, tr;
tr = '';
ref = json.data;
for (j = 0, len = ref.length; j < len; j++) {
i = ref[j];
tr + '<tr><td>' + i.a + '-' + i.b + '</td><td>' + i.c + '</td><td>' + i.d + '</td></tr>';
}
return tr;
};
The only difference is a missing assignment. The CoffeeScript version should be:
createTr = (json) ->
tr=''
tr += '<tr><td>' + i.a + '-' + i.b+'</td> <td>'+i.c+'</td><td>'+i.d+'</td></tr>' for i in json.data
tr
##.coffee file
createTr = (json) ->
tr = ''
for item in json.data
data = """<tr>
<td>#{item.a}-#{item.b}</td>
<td>#{item.c}</td>
<td>#{item.d}</td></tr> """
tr += data
return tr
And read http://coffeescript.org/ about loop, string and variables in string like "Some text #{variable}"
I prefer to use a join on the array that the for loop creates:
createTr = (json) ->
('<tr><td>' + i.a + '-' + i.b+'</td> <td>'+i.c+'</td><td>'+i.d+'</td></tr>' for i in json.data).join("")
or kind of like @yavor.makc if it was my code I might focus on readability:
createTr = (json) ->
(for i in json.data
"
<tr>
<td>#{i.a}-#{i.b}</td>
<td>#{i.c}</td>
<td>#{i.d}</td>
</tr>
"
).join("")
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.