Dynamically adding x number of days to a date in PHP

Question

I have a scenario where I have to add x number if days to a variable containing date. This x will be dynamic and cannot be guessed.

Any suggestions on how I can implement this?

$ticket_created_on_date_time = '2016-08-31 09:55:01'
$in_between_days = 2;

Answer 1

A quick example:

<?php
$date = new DateTime($ticket_created_on_date_time);
$date->add(new DateInterval(sprintf('P%dD', $in_between_days)));
echo $date->format('Y-m-d H:i:s'); //output: 2016-09-02 09:55:01

More details in http://php.net/manual/en/datetime.add.php

Answer 2

You can use math and the strtotime function to get a date in the past/future. Something like:

strtotime($ticket_created_on_date_time) + (86400 * $in_between_days)

(86400 is one day in seconds) ....or

strtotime($ticket_created_on_date_time . '+ ' . $in_between_days . ' days')

Demo: https://eval.in/634187

Answer 3

You should be doing it like this,

<?php
$date = new DateTime($ticket_created_on_date_time);
$date->modify("+2 day");
echo $date->format("r");

Edit - You can modify dynamically like this:

$date->modify(sprintf("%u day",$day_diff));