Javascript Function.prototype.call() pass primitive value

Question

I want to pass an index-variable as this to a function I call with function.call() .

var fun = function() {
    console.log( this );
}

fun.call( 1 );
// -> Number {[[PrimitiveValue]]: 1}

So obviously the primitive integer 1 is not passed as primitive to the called function.
According to MDN for Function.prototype.call() "[...] primitive values will be converted to objects."

Is there a way to pass it to fun() as primitive integer?

Answer 1

In the above example 1 is passed as an integer param but internally it is a object of number type to the fun function. So in order to access the value of integer from this . Use this.valueOf() . I think this helps you!

 var x = 12; function fun() { console.log(this.valueOf()); } fun.call(x) 

Answer 2

Well what you want is never possible as per the definition of this inside a function. Yes there can be way arounds as given in the other answers for your implementation.