Compare two tables and find the unmatch record

Question

I would like to compare two different tables with almost desame column names and output them by marking 1 on columns with same value and 0 with indifferent values given the ID columns are untouched.

Table 1

ID | Value | Color
1  | good  | red
2  | bad   | blue

Table 2

ID | Value | Color
1  | any   | red
2  | bad   | blue

Output

ID | Value | Color
1  | 0     | 1
2  | 1     | 1

wherein, the 0 is the value with different column values.

Answer 1

SELECT table1.id, 
  CASE WHEN table1.value=table2.value THEN 1 ELSE 0 END AS value,
  CASE WHEN table1.color=table2.color THEN 1 ELSE 0 END AS color
FROM table1 JOIN table2 ON table2.id=table1.id
ORDER BY 1;

or shorter approach:

SELECT table1.id, (table1.value=table2.value) AS value, (table1.color=table2.color) AS color
FROM table1 JOIN table2 ON table2.id=table1.id
ORDER BY 1;

Approach in MySQL-syntax:

SELECT table1.id,
  IF(table1.value=table2.value, 1, 0) AS value,
  IF(table1.color=table2.color, 1, 0) AS color
FROM table1 JOIN table2 ON table2.id=table1.id
ORDER BY 1;