I'm trying to get the (x,y) location of where a button is tapped. I've found answers but they don't work for Swift 2.3. Any suggestions? That's what I have tried:
@IBAction func buttonTapped(sender: AnyObject, forEvent event: UIEvent) {
let buttonView = sender as! UIView;
// get any touch on the buttonView
if let touch = event.touchesForView(buttonView) as? UITouch{
// print the touch location on the button
print(touch.locationInView(buttonView))
}
}
Swift 2:
@IBAction func buttonPressed(button: UIButton, forEvent event: UIEvent) {
guard let touch = event.allTouches()?.first else { return }
let point = touch.locationInView(button)
print ("point: \(point)")
}
Swift 3:
@IBAction func buttonPressed(_ button: UIButton, forEvent event: UIEvent) {
guard let touch = event.allTouches?.first else { return }
let point = touch.location(in: button)
print ("point: \(point)")
}
To create an IBAction with event pick the right option in this popup in your storyboard:
func addGesture() {
let gestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(ViewController.buttonTapped(sender:)));
gestureRecognizer.numberOfTapsRequired = 1;
gestureRecognizer.numberOfTouchesRequired = 1;
button.addGestureRecognizer(gestureRecognizer) }
func buttonTapped(sender:UIGestureRecognizer) {
print(sender.location(in: button))
}
You can add Gesture recognizer to UIButton and it will work as well
override func touchesBegan(touches: NSSet!, withEvent event: UIEvent!) {
let touch = touches.allObjects[0] as UITouch
let touchLocation = touch.locationInView(self.view)
}
Hope this will be useful
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.