I try to figure out how to configure routing in my application with lazy loaded modules.
For instance I have a lazy module called AnimalsModule, and I want that this module handle 2 routes "/cats" and "/dogs".
In current router api I need to specify common path for all lazy module routes, like: 'animals/dogs' and 'animals/cats'.
{
path: "animals",
loadChildren: "animals"
}
I can specify empty path for AnimalsModule:
{
path: "",
loadChildren: "animals"
},
{
path: "foo",
component: FooComponent
}
But in this case AnimalsModule will be unnecessary loaded when user navigates to "/foo" resource.
If I create 'animals/cats' and 'animals/dogs' routes and in the future I want to refactor my code to split AnimalsModule into DogsModule and CatsModule (also lazy), I will have to break my application routes. (same for merge)
How to create routing with lazy module without common path?
路由具有一个称为matcher
property see docs的属性,您可以在其中提供自己的路由匹配逻辑,但是正如在问题注释中所述,我实际上是创建2条路由,甚至将它们分成2个模块(更有可能)。
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