In batch, how to list files of a specific directory?

Question

I need to go through all the directories except one (named "FORBIDDEN"), and to print for each of them all the files they contain.

So I wrote a batch script like this:

@echo off
for /f "tokens=*" %%G in ('dir /b /s /a:d %cd%') do ^
if %%G NEQ C:\Users\ME\FORBIDDEN (dir /a-d %%G)

But the part (dir /ad %%G) is not good because I get some errors saying that files were not find.

So, for each round of the loop, how to list all files present in the directory (whose path is in %%G ) ?

Cheers

Answer 1

for /d /r %%d in (*) do if not "%%~nxd"=="FORBIDDEN" 2>nul dir /a-d "%%d"

For each folder if it is not the excluded one, show its contents

edited to adapt to comments

To only include the files with full path

for /d /r %%d in (*) do if not "%%~nxd"=="FORBIDDEN" (
    for %%f in ("%%~fd") do echo "%%~ff"
)

Another option (that also includes files in the current folder) could be

dir /a-d /s /b | find /v "\FORBIDDEN\"

Get the full list and filter it, to only retrieve the lines that does not make reference to the excluded folder