This is my dataset:
set.seed(327)
ID <- seq(1:50)
mou <- sample(c(2000, 2500, 440, 4990, 23000, 450, 3412, 4958, 745, 1000),
50, replace=TRUE)
calls <- sample(c(50, 51, 12, 60, 90, 16, 89, 59, 33, 23, 50, 555),
50, replace=TRUE)
rev <- sample(c(100, 345, 758, 44, 58, 334, 888, 205, 940, 298, 754),
50, replace=TRUE)
dt <- data.frame(mou, calls, rev)
My motive is to find the mean of mou
where calls is greater than 34 and less than 200 and rev
greater than 100 and less than 400. I started approaching this problem by using dplyr but I am not so sure how to correctly use the desired expression inside filter function.
dt %>% filter(???) %>% summarize(mean_mou=mean(mou))
Could you please guide how to frame this expression inside filter correctly.
For completeness:
If the logic is AND you can simply add multiple condition after a comma:
df %>%
filter(calls > 34, calls < 200, rev > 100, rev < 400)
If the logic is OR you must use the usual logic or
symbol: |
df %>%
filter(calls > 34 | rev > 100)
Chaining them together work, but one must pay attention to what is done. For example:
df %>%
filter(calls > 34, calls < 200 | rev > 100, rev < 400)
means calls > 34 AND (calls < 200 OR rev > 100) AND rev < 400
You can put your conditionals in the filter
function. You're almost there in your example :-)
########
# Setup
########
set.seed(327) # Setting a seed makes the example reproducible
ID <- seq(1:50)
mou <-
sample(c(2000, 2500, 440, 4990, 23000, 450, 3412, 4958, 745, 1000),
50,
replace = TRUE)
calls <-
sample(c(50, 51, 12, 60, 90, 16, 89, 59, 33, 23, 50, 555), 50, replace = TRUE)
rev <-
sample(c(100, 345, 758, 44, 58, 334, 888, 205, 940, 298, 754), 50, replace = TRUE)
dt <- data.frame(mou, calls, rev)
library(tidyverse)
########
# Here's the direct answer to your question
########
dt %>%
filter(calls > 34 & calls < 200) %>%
filter(rev > 100 & rev < 400) %>% # Using two filters makes things more readable
summarise(mean_mou = mean(mou))
# 3349
dt %>%
filter(., calls > 40 & calls < 200 & rev > 100 & rev <400) %>%
summarise( mean(mou))
mean(mou)
1 2403.333
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