I have a from like this:
With the following code:
<form onKeyPress={this.login.bind(this)}>
<input type="text" placeholder="username"/>
<input type="password" placeholder="password"/>
<button type="button" onClick={this.login.bind(this)}>Log In</button>
</form>
While I have the login()
method like below:
login(e){
if((e.type==='keypress' && e.which===13) || e.type==='click'){
//Do login operations:
this.props.store.login()//the method inside MobX store
}
}
On following scenarios, there is no errors and I can login:
login
button with mouse But the following 3rd scenario, gives me errors due to the login operations being called twice:
I wonder what is the best practice by which I can avoid the errors of 3rd scenario. I looked through other related SO questions but I couldn't figure out the best practice.
I forgot to mention I'm using ReactJS with MobX.
Solved the problem by moving onKeyPress
attribute from <form>
tag to text-type <input>
tags:
<form>
<input type="text" placeholder="username" onKeyPress={this.login.bind(this)}/>
<input type="password" placeholder="password" onKeyPress={this.login.bind(this)}/>
<button type="button" onClick={this.login.bind(this)}>Log In</button>
</form>
You could also use the onSubmit
event if it suits your use case better:
Example ( JS Bin )
class App extends Component {
login = (e) => {
e.preventDefault();
console.log('login');
}
render() {
return (
<form onSubmit={this.login}>
<input type="text" placeholder="username" />
<input type="password" placeholder="password" />
<button type="submit">Log In</button>
</form>
);
}
}
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