I have the following tibble:
library(tidyverse)
df <- structure(list(`Input paired-end (STAR)` = c(9394981, 100), `Multi-mapped pair (STAR)` = c(1493691,
400), `Uniquely mapped paired-end (STAR)` = c(6826405, 200),
`Unmapped pair (STAR-appx)` = c(1074885, 300)), class = c("tbl_df",
"tbl", "data.frame"), row.names = 1:2, .Names = c("Input paired-end (STAR)",
"Multi-mapped pair (STAR)", "Uniquely mapped paired-end (STAR)",
"Unmapped pair (STAR-appx)"))
That looks like this:
# A tibble: 2 × 4
`Input paired-end (STAR)` `Multi-mapped pair (STAR)` `Uniquely mapped paired-end (STAR)` `Unmapped pair (STAR-appx)`
* <dbl> <dbl> <dbl> <dbl>
1 9394981 1493691 6826405 1074885
2 100 400 200 300
How can I rename the column too:
foo bar qux gop
9394981 6826405 1074885 1493691
100 200 300 400
An easy option is with setNames
which can also be incorporated into the chain
library(dplyr)
df %>%
setNames(., c('foo', 'bar', 'qux', 'gop'))
If you really wanted to use `dplyr functions, you would use rename
df %>% rename(foo=`Input paired-end (STAR)`,
bar=`Multi-mapped pair (STAR)`,
qux=`Uniquely mapped paired-end (STAR)`,
qop=`Unmapped pair (STAR-appx)`)
But it would be much easier with base functions
names(df) <- c("foo","bar","qux","qop")
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