Get column value by name rather than position in cx_Oracle

Question

Using cx_Oracle , I am selecting data from an Oracle database.

curs = cxn.cursor()
result = curs.execute(SELECT FirstName, LastName FROM Person)

Is there a way to return only the firstname without numerical index? For example:

for row in result:
    result[0] #will return the first column

What I am hoping to do is call the value like result['FirstName']

Answer 1

Using cx_Oracle , I am selecting data from an Oracle database.

curs = cxn.cursor()
result = curs.execute(SELECT FirstName, LastName FROM Person)

Is there a way to return only the firstname without numerical index? For example:

for row in result:
    result[0] #will return the first column

What I am hoping to do is call the value like result['FirstName']

Answer 2

Using cx_Oracle , I am selecting data from an Oracle database.

curs = cxn.cursor()
result = curs.execute(SELECT FirstName, LastName FROM Person)

Is there a way to return only the firstname without numerical index? For example:

for row in result:
    result[0] #will return the first column

What I am hoping to do is call the value like result['FirstName']

Answer 3

nmcol=[row[0] for row in c.description]
# print(nmcol)
for row in cursor:
  print(row[nmcol.index('FirstName')])