I'm hoping a Python expert out there can offer some assistance on the confusion I'm experiencing currently with Inner Functions, Closures, and Factory Functions. Upon looking for an implemented example of a General Hough Transform I found this:
https://github.com/vmonaco/general-hough/blob/master/src/GeneralHough.py
I'd like to translate this into C++ and it seems the first step is to factor out the inner function in general_hough_closure():
def general_hough_closure(reference_image):
'''
Generator function to create a closure with the reference image and origin
at the center of the reference image
Returns a function f, which takes a query image and returns the accumulator
'''
referencePoint = (reference_image.shape[0]/2, reference_image.shape[1]/2)
r_table = build_r_table(reference_image, referencePoint)
def f(query_image):
return accumulate_gradients(r_table, query_image)
return f
I seem to be stuck on how this function works. "f" does not seem to be called anywhere, and I'm not sure how the function knows what "query_image" is? I'v tried various Googling to find tips on Inner Functions, Closures, and Factory Functions, for example this and some similar pages, but all the examples I can find are more simplified and therefore not much help. Can anybody offer some direction?
The code is just returning the function f
as a whole thing. There's no need to "know what the argument is" -- f
will know it at the time it is called. The classic example is this:
>>> def f(x):
... def g(y):
... return x + y
... return g
...
>>> f
<function f at 0x7f8500603ae8>
>>> f(1)
<function f.<locals>.g at 0x7f8500603a60>
>>> s = f(1)
>>> s(2)
3
Here, as in your function, g
closes over another value ( x
or r_table
, respectively), while still expecting its actual argument.
Since there is a closed-over value, you cannot directly factor out f
. One traditional approach is to return an object containing the value, which has some kind of call method representing the function; the easier way in C++ nowadays is to use a lambda function:
int f(int x) {
auto g = [x](int y) {
return x + y
};
return g;
}
In C++ you have the "advantage" that it will yell at you if don't specify which values you are closing over (that's the [x]
here). But internall, it does pretty much the same thing (constructing an anonymous class with an x
-member).
C++ before C++11 does not have function as type.
You can use the following class to emulate the semantics (pseudo code):
class GeneralHoughClosure {
public:
GeneralHoughClosure(reference_image) {
referencePoint = (reference_image.shape[0]/2, reference_image.shape[1]/2)
r_table = build_r_table(reference_image, referencePoint)
}
void Run(queryImage) {
return accumulate_gradients(r_table, query_image)
}
void operator()(queryImage) {
return accumulate_gradients(r_table, query_image)
}
}
Then, you can use it as follows:
gg = new GeneralHoughClosure(reference_image)
gg.Run(queryImage1)
gg(queryImage2)
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