How to handle HTTP/1.1 403 Forbidden from PHP code
Question
I am using the API sometimes it will return the HTTP/1.1 403 Forbidden message. How should I handle this in code?
I want if API return 403 Forbidden skip the below code and if its return the success continue with the below code.
Anyone can tell me how to handle the HTTP/1.1 403 Forbidden in php code?
Return a code as below,
<html>
<head><title>403 Forbidden</title></head>
<body bgcolor="white">
<center><h1>403 Forbidden</h1></center>
<hr><center>nginx</center>
</body>
</html>
unable to check status code.
2 answers
solution1
1 2017-05-04 11:17:42
var_dump(http_response_code());
您可以使用此检查响应，然后根据发送的响应执行您需要的操作
solution2
0 ACCPTED 2017-05-04 13:30:10
With the help of PHP's " get_headers " function I have get the status code easily and solve my problem,
get_headers($URL, 1); // will return all the headers sent by the server in response.
If it will return 200 then I will continue execute the script otherwise stop there.
When I print the response of get_header it will like below,
For Success(200) response as below,
Array
(
[0] => HTTP/1.1 200 OK
[Date] => Thu, 04 May 2017 12:38:41 GMT
[Content-Type] => text/plain; charset=utf-8
[Content-Length] => 725
[Connection] => close
[Server] => Apache
[Cache-Control] => max-age=0
[Expires] => Thu, 04 May 2017 12:38:41 GMT
)
And For 403 Forbidden
Array
(
[0] => HTTP/1.1 403 Forbidden
[Server] => geoPlugin
[Date] => Thu, 04 May 2017 12:41:30 GMT
[Content-Type] => text/html
[Connection] => close
)
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