I am building a flow like this
FirstViewController -> SecondViewController - > Tab Bar View Controller (consists of 1. ThirdViewController and 2. FourthVIewController)
I am opening Tab Bar View Controller as a pop up form the SecondViewController. However, when I run (self.dismiss(animated: true, completion: nil)) on click of a button in ThirdViewController, it goes back to the FirstViewController. I want to go back to the SecondViewController
Adding code. This is how I open the tab bar view controller from my SecondViewController
let popupVC = UIStoryboard(name: "Main", bundle: nil).instantiateViewController(withIdentifier: "tabBarVC") as! UITabBarController
self.addChildViewController(popupVC)
popupVC.view.frame = self.view.frame
self.view.addSubview(popupVC.view)
popupVC.didMove(toParentViewController: self)
And this is how I try to close the tab bar view controller form Third View Controller
self.dismiss(animated: true, completion: nil))
You added tabBarController in secondViewController as subView. So you need to remove that tabBarController view from super view.
For that, you need a tabBarController object.
self.tabBarController?.view.removeFromSuperview()
You can use a navigation controller in your flow, so when you are in ThirdViewController use this:
if let vc = self.storyboard?.instantiateViewController(withIdentifier: "second") as? SecondViewController {
self.navigationController?.popToViewController(vc, animated: true)
}
下面的代码能够删除 tabview 并带我回到 SecondViewController
self.tabBarController?.view.removeFromSuperview()
切换到 UITabBar 上的其他项,其中 0 插入 UTTabBar 项的索引:
self.tabBarController?.selectedIndex = 0
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