I had a form that when I clicked on submit it was submitted. Then that form hid and the result of action page showed in div with classname= dig
.
It was working correctly but when I added another forms it stopped working correctly and all of the forms submitted at the same time.
How can I change my code?:
$(".done").click(function(e) { var url = 'http://seller.ir/test' $.ajax({ type: "POST", url: url, data: $(".formi").serialize(), success: function(data) { $('.dig').empty() $('.dig').html(data) } }); e.preventDefault(); });
.dig { width: 200px; height: 30px; border: 1px solid #000 }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script> <div class="dig"> <form class="formi"> <button class="done">done</button> </form> </div> <div class="dig"> <form class="formi"> <button class="done">done</button> </form> </div> <div class="dig"> <form class="formi"> <button class="done">done</button> </form> </div>
$(".done").click(function(e) {
var dig=$(this).parents('.dig');
var url = 'http://seller.ir/test'
$.ajax({
type: "POST",
url: url,
data: $(this).parent('.formi').serialize(),
success: function(data) {
$(dig).empty()
$(dig).html(data)
}
});
e.preventDefault();
});
you should empty and fill the corresponding dig
element only as
$(".done").click(function(e) {
var url = 'http://seller.ir/test';
var digElement=$(this).parents('.dig');
$.ajax({
type: "POST",
url: url,
data: $(this).parent('.formi').serialize(),
success: function(data) {
digElement.html(data)
}
});
e.preventDefault();
});
Try with form
submit and $(that).closest('.dig').empty()
to find the .dig
.In this snippet is not working .Snippet blocked some ajax function call
change the button as type="submit"
Note create the ajax function is separate and call with new ajax
like constructor .Its not disturbing on going ajax
$(document).ready(function(){ $("form").on('submit',function(e) { var url = 'http://seller.ir/test'; new ajax($(this)) e.preventDefault(); }); }) function ajax(that){ $.ajax({ type: "POST", url: url, data: $(that).serialize(), success: function(data) { $(that).closest('.dig').empty() }, error:function(jqXHR, textStatus, errorThrown){ console.log(textStatus) } }); }
.dig { width: 200px; height: 30px; border: 1px solid #000 }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script> <div class="dig"> <form class="formi"> <button class="done" type="submit">done</button> </form> </div> <div class="dig"> <form class="formi"> <button class="done" type="submit">done</button> </form> </div> <div class="dig"> <form class="formi"> <button class="done" type="submit">done</button> </form> </div>
$(".done").click(function(e) { var url = 'http://seller.ir/test' $.ajax({ type: "POST", url: url, data: $(this).parents("form").serialize(), success: function(data) { $(this).parents("dig").empty() $(this).parents("dig").html(data) } }); e.preventDefault(); });
.dig { width: 200px; height: 30px; border: 1px solid #000 }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script> <div class="dig"> <form class="formi"> <button class="done">done</button> </form> </div> <div class="dig"> <form class="formi"> <button class="done">done</button> </form> </div> <div class="dig"> <form class="formi"> <button class="done">done</button> </form> </div>
Try This!And send update if it doesn't work.
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