code2flow can't find graphviz in the path

Question

I'm trying to get some code to run and I'm triggering an error:

if not isInstalled('dot') and not isInstalled('dot.exe'):
    print "You must have graphviz (specifically dot) installed to run code2flow"
    sys.exit(1)

which calls

def isInstalled(program):
    def is_exe(fpath):
        return os.path.isfile(fpath) and os.access(fpath, os.X_OK)

    for path in os.environ["PATH"].split(os.pathsep):
        path = path.strip('"')
        exe_file = os.path.join(path, program)
        if is_exe(exe_file):
            return True

    return False

But I don't understand why this is failing. My path contains graphviz

> echo %PATH%

...;c:\\Program Files (x86)\\Graphviz2.38\\bin;...

and the file is present

> dir "c:\\Program Files (x86)\\Graphviz2.38\\bin\\dot.exe"

Directory of c:\\Program Files (x86)\\Graphviz2.38\\bin

04/14/2014 09:22 AM 7,680 dot.exe

Any ideas of what is going wrong?

Answer 1

I have this error, too.

I try to run the command:

sudo python setup.py install

It's okay now.

My way to install code2flow is by using pip install.

But the codes inside ./ur/path/to/code2flow is written with python2.

Thus!