Selecting all XML elements and their values dynamically using LINQ

Question

I have the following code which dynamically selects all of the distinct element names, however; I also want to see the values for these elements. How can I do this using LINQ? I am open to doing it other ways as well.

 XDocument doc = XDocument.Load("XMLFile1.xml");
 foreach (var name in doc.Descendants("QueryResults").Elements()
                .Select(x => x.Name).Distinct())
 {
 }

Answer 1

Something like this would work

   XDocument doc = XDocument.Load("XMLFile1.xml");
   foreach (var name in doc.Descendants("QueryResults").Elements()
                .Select(x => new {Name = x.Name, Value = e.Value}).Distinct())
   {


   }

Answer 2

The accepted query is differnt then the original one because it changes how Distinct works because it no longer compares only Name but also Value . If you want to see which names have which values you need to use GroupBy on the Name and get the Value for each item.

var results =
    doc
        .Descendants("QueryResults")
        .Elements()
        .GroupBy(x => x.Name, (name, items) => new
        {
            Name = name,
            Values = items.Select(x => x.Value)
        });

Answer 3

您只需使用name.Value ，它是XElement的字符串属性。