Im trying to get a similar signal from a code in Matlab with python.
Code in MATLAB:
Fs = 1e3; % sampling frequency (in Hz)
L = 1e5; % signal length (number of samples)
f0 = 0.1*Fs; % cycle frequency (in Hz)
x = rand(L, 1);
a = [1 -2*cos(2*pi*.2)*.9 .9^2];
x = filter(1,a,x);
x = x.*(1 + sin(2*pi*(0:L-1)'*f0/Fs));
x = x +std(x)*rand(L,1);
histogram(x,100);
Code in Python:
Fs=10**3
L=10**5
f0=0.1*Fs
x=np.random.normal(0,1,L)
a=[1,-2*np.cos(2*np.pi*.2)*.9,.9**2]
x=sps.lfilter([1],a,x)
Random_modulated_signal=x*(1+np.sin(2*np.pi*np.arange(0,L)*f0/Fs))
Rms_Whitenoise=x+np.std(x)*np.random.normal(0,1,L)
plt.hist(Rms_Whitenoise,bins=100,edgecolor='k')
plt.show()
If I plot a histogram of both signals, they dont share the same behaviour. The signals differ when I add std(x)*rnd(L,1)
.
What is strange is that I used the same codes as shown before, but instead of using a normal distribution, I used rand('twister', 2)
and np.random.seed(2)
for generating same values in both programs and it worked.
Please can someone clarify what am I am doing wrong?
Matlab's rand
is a uniform random distribution, not a normal distribution. The equivalent of numpy.random.normal
in matlab is randn
. The numpy equivalent of matlab's rand
is numpy.random.random
.
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