I have two buttons in the form. I want to disable both of these buttons when I press one of these two buttons. And want to show the dialogue modal when I press login button. However, It can't work well in this part. Here is my code!
$(function(){
$(".js-disable-form-individual").on("submit", function() {
$('.js-disable]-btn').click(function() {
$('#loading-modal').modal('show');
})
$(this).find("input[type=submit]").prop('disabled', true);
})
});
Thank you for answering.
Change your js code to this,
$(function(){
$(".text-center input[type=submit]").on("click", function(event) {
event.preventDefault();
$(".text-center input[type=submit]").prop('disabled', 'disabled');
});
$('.js-disable-btn').on("click",function(){
$('#loading-modal').modal('show');
});
$('#finalSubmit').on("click",function(){
$(".js-disable-form-individual").submit();
});
});
*Say if you have a button which id is finalSubmit
on the dialog (which you want to submit form on click),
I'm not sure, try to separate them?
$(function(){
$(".js-disable-form-individual").on("submit", function() {
e.preventDefault();
$(this).find("input[type=submit]").prop('disabled', true);
})
$('.js-disable-btn').on('click',function() {
$('#loading-modal').modal('show');
})
});
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