How to create a Conda environment based on a YAML file?

Question

I am working on a online course and the instructors have asked me to create a Conda environment, and they have provided a YAML file to provide the library and package requirements for the Conda package.

However, I am unable to find a way to create the environment using the YAML file.

Answer 1

conda env create takes an optional flag --file :

-f FILE, --file FILE environment definition file (default: environment.yml)

So do:

conda env create --file=myfile.yaml

Of course, replace =myfile.yaml with your YAML file name.

Answer 2

Use:

conda env create --name NAME --file FILE

where FILE is the YAML file and NAME is what you want to name the environment.

(The accepted answer used to suggest conda create , but that only works on the output of conda list --explicit , not on Conda environment YAML files.)

Answer 3

conda env create --file=dand-env-win.yaml

对我来说效果很好，我的文件名是dand-env-win.yaml用于互联网上的课程 。