How to find an element with some parts of href value ? (python selenium)

Question

I have some parts of value of href(ex. The href's query value) not a full value. In this case, what method is the best to select an element (for clicking, sending keys, etc) ?

I have tried with many ways but they do not work very well. Especially, after getting html source, with 're' module, I extraced the full href. And then, I used 'webdriver.find_element(By.XPATH, "//a[@href='the full href']") But It results to 'NoSuchElementError'. ( I assume that the server continuously changes some parts of href)

Anyway,, what is the best method to find and select element only with some parts of href value ? (python3.6 / selenium module / PhantomJS)

Answer 1

Href containing value

//a[contains(@href, 'part/of/href')]

Href that starts with value

//a[starts-with(@href, 'http://start.of.href.')]

another option - to search not by href by itself, but By.linkedText() - possible in java with selenium, i'm not aware if possible in python

driver.findElement(By.linkedText("some linked text inside a attribute"));

Answer 2

Try this:

webdriver.find_element(By.XPATH, "//a[@href='" + the_full_href + "']")

This will work if the_full_href is a variable

Answer 3

Href包含值

driver.find_element_by_partial_link_text('partial href text here')