Bash sed command replace with output of a command

Question

I'm working on one of my first bash scripts on mac. My goal is to read the name of my git branch , save it into the terminal variable PR_TITLE and then finally replace the placeholder pull_request_name with the variable $PR_TITLE using sed -i .

Below are the terminal commands I am running. Setting the variable is working fine but I am unable to replace the placeholder with the variable. Currently bash outputs the following when I run my sed command. -bash: feature/issues-5-6: No such file or directory

PR_TITLE=$( git branch | grep \* | tr -d '*' )

sed -i '' "s/\pull_request_name/$($PR_TITLE)/" /Users/$USER/Desktop/PR_File.txt

Answer 1

您可以使用内部引号" bash命令替换命令$(command) 。要避免这种情况，您需要先引号$ 。

sed -i '' "s/\pull_request_name/\$($PR_TITLE)/" /Users/$USER/Desktop/PR_File.txt